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#🚨UPSC Exams📚
#📖बैंकिंग की तैयारी
#📚एजुकेशन टिप्स & ट्रिक्स✍
#📚प्रतियोगी परीक्षा विशेष🏆
#📢SSC की परीक्षा📋
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![🚨UPSC Exams📚 - CALCULUS DIFFERENTIATION INTEGRATION FORMULAS FORMULAS (x)=1 J dx = X+C ) ) dX > Jadx-ax+c )d()=0 dx n+1 > ] x"dx = )d(xn) = nxn-1 +C X 1+1 dx Jsinxdx = -cos + C > d (cosx) =-sin x > dX Jcosx dx= sinx +c d_(sinx) = cosx > 7 dx [secx dx=tanxtc > 4 (tanx) = sec? x ১ dx J secxltanxldx =secx+C > d (cscx) = ~cscxot > dX >[ Xdx= InlxI+ C > 4 (Inx)-X dx > d (e*) = ex > ] edx =ex+C dx > fa"dx= G*€ > d (sin 'x) = dX > [4x= sin X+c > d (COs-'x) = dX >[=1,= cosx+C > d (tan-'x) = 1+x dx Jidx-tan-'x+c d(ino) (a*) >d > 3 dx CALCULUS DIFFERENTIATION INTEGRATION FORMULAS FORMULAS (x)=1 J dx = X+C ) ) dX > Jadx-ax+c )d()=0 dx n+1 > ] x"dx = )d(xn) = nxn-1 +C X 1+1 dx Jsinxdx = -cos + C > d (cosx) =-sin x > dX Jcosx dx= sinx +c d_(sinx) = cosx > 7 dx [secx dx=tanxtc > 4 (tanx) = sec? x ১ dx J secxltanxldx =secx+C > d (cscx) = ~cscxot > dX >[ Xdx= InlxI+ C > 4 (Inx)-X dx > d (e*) = ex > ] edx =ex+C dx > fa"dx= G*€ > d (sin 'x) = dX > [4x= sin X+c > d (COs-'x) = dX >[=1,= cosx+C > d (tan-'x) = 1+x dx Jidx-tan-'x+c d(ino) (a*) >d > 3 dx - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_781522_7effa15_1763114779525_sc.jpg?tenant=sc&referrer=pwa-sharechat-service&f=525_sc.jpg "🚨UPSC Exams📚 - CALCULUS DIFFERENTIATION INTEGRATION FORMULAS FORMULAS (x)=1 J dx = X+C ) ) dX > Jadx-ax+c )d()=0 dx n+1 > ] x\"dx = )d(xn) = nxn-1 +C X 1+1 dx Jsinxdx = -cos + C > d (cosx) =-sin x > dX Jcosx dx= sinx +c d_(sinx) = cosx > 7 dx [secx dx=tanxtc > 4 (tanx) = sec? x ১ dx J secxltanxldx =secx+C > d (cscx) = ~cscxot > dX >[ Xdx= InlxI+ C > 4 (Inx)-X dx > d (e*) = ex > ] edx =ex+C dx > fa\"dx= G*€ > d (sin 'x) = dX > [4x= sin X+c > d (COs-'x) = dX >[=1,= cosx+C > d (tan-'x) = 1+x dx Jidx-tan-'x+c d(ino) (a*) >d > 3 dx CALCULUS DIFFERENTIATION INTEGRATION FORMULAS FORMULAS (x)=1 J dx = X+C ) ) dX > Jadx-ax+c )d()=0 dx n+1 > ] x\"dx = )d(xn) = nxn-1 +C X 1+1 dx Jsinxdx = -cos + C > d (cosx) =-sin x > dX Jcosx dx= sinx +c d_(sinx) = cosx > 7 dx [secx dx=tanxtc > 4 (tanx) = sec? x ১ dx J secxltanxldx =secx+C > d (cscx) = ~cscxot > dX >[ Xdx= InlxI+ C > 4 (Inx)-X dx > d (e*) = ex > ] edx =ex+C dx > fa\"dx= G*€ > d (sin 'x) = dX > [4x= sin X+c > d (COs-'x) = dX >[=1,= cosx+C > d (tan-'x) = 1+x dx Jidx-tan-'x+c d(ino) (a*) >d > 3 dx - ShareChat")