INSTALL
लोकप्रिय
NIRAJ KUMAR YADAV
16.2K ने देखा
#🧮 सरल गणित / Reasoning
#📚एजुकेशनल ज्ञान📝
#👨🏫️स्किल डेवलपमेंट👔
#📚एजुकेशन टिप्स & ट्रिक्स✍
#📚प्रतियोगी परीक्षा विशेष🏆
63
67
2
Your browser does not support JavaScript!
![🧮 सरल गणित / Reasoning - बीजगणित सूत्र (a+b)2/ a१ + २ab + b२ = (a-b)2 = a?_ 2ab+b2 @7+62 = (@+6)2-2ab a2_b2 = (a+b)(a-b) = (a+b)2 = (a-b)2+ 4ab] (0+b)2 _ 40b | (a ~ b)2 3 (a-b)2 + 2ab 02+ 62 . 9 2(02+b2) = (+b)?+ (-b)2' (a+b)2_ (a-b)2 40b 3 (02b)2 _ (%b)2 ab a3+3a2b+3ab2+63 (a+b)3 = (a+b)3 @3+63+ 3ab(a+b) = @3-3@%b+3@b2-63 (0-b)3 > @-b) = @ -30 = 3ab(a-b) a3+b3 = (a+b)(a?-ab+b2) : Q3 + b3 = (+b)3 _ 3ಯb(o+b) (a-b)(a?+ab+b2) @3-63 = a3_63 = (a-b)3 + 3ab(a-b) (+b+C)2 = (2+b2+c2) + 2(0b+bc+ca) > (a2+62+c2) = (a+b+c)?_2(ab+bc+ca) > 2(abtbctca) = (a+b+c)?_(a2+b2+c2) (+b+c)3 = 03+63+c3+3(0+b) (b+c)(c+a) a3+b3+c3_3abc-(atbtc)(a?+b+c?-ab-bc 00 बीजगणित सूत्र (a+b)2/ a१ + २ab + b२ = (a-b)2 = a?_ 2ab+b2 @7+62 = (@+6)2-2ab a2_b2 = (a+b)(a-b) = (a+b)2 = (a-b)2+ 4ab] (0+b)2 _ 40b | (a ~ b)2 3 (a-b)2 + 2ab 02+ 62 . 9 2(02+b2) = (+b)?+ (-b)2' (a+b)2_ (a-b)2 40b 3 (02b)2 _ (%b)2 ab a3+3a2b+3ab2+63 (a+b)3 = (a+b)3 @3+63+ 3ab(a+b) = @3-3@%b+3@b2-63 (0-b)3 > @-b) = @ -30 = 3ab(a-b) a3+b3 = (a+b)(a?-ab+b2) : Q3 + b3 = (+b)3 _ 3ಯb(o+b) (a-b)(a?+ab+b2) @3-63 = a3_63 = (a-b)3 + 3ab(a-b) (+b+C)2 = (2+b2+c2) + 2(0b+bc+ca) > (a2+62+c2) = (a+b+c)?_2(ab+bc+ca) > 2(abtbctca) = (a+b+c)?_(a2+b2+c2) (+b+c)3 = 03+63+c3+3(0+b) (b+c)(c+a) a3+b3+c3_3abc-(atbtc)(a?+b+c?-ab-bc 00 - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_73072_29fc3e01_1769078071459_sc.jpg?tenant=sc&referrer=pwa-sharechat-service&f=459_sc.jpg "🧮 सरल गणित / Reasoning - बीजगणित सूत्र (a+b)2/ a१ + २ab + b२ = (a-b)2 = a?_ 2ab+b2 @7+62 = (@+6)2-2ab a2_b2 = (a+b)(a-b) = (a+b)2 = (a-b)2+ 4ab] (0+b)2 _ 40b | (a ~ b)2 3 (a-b)2 + 2ab 02+ 62 . 9 2(02+b2) = (+b)?+ (-b)2' (a+b)2_ (a-b)2 40b 3 (02b)2 _ (%b)2 ab a3+3a2b+3ab2+63 (a+b)3 = (a+b)3 @3+63+ 3ab(a+b) = @3-3@%b+3@b2-63 (0-b)3 > @-b) = @ -30 = 3ab(a-b) a3+b3 = (a+b)(a?-ab+b2) : Q3 + b3 = (+b)3 _ 3ಯb(o+b) (a-b)(a?+ab+b2) @3-63 = a3_63 = (a-b)3 + 3ab(a-b) (+b+C)2 = (2+b2+c2) + 2(0b+bc+ca) > (a2+62+c2) = (a+b+c)?_2(ab+bc+ca) > 2(abtbctca) = (a+b+c)?_(a2+b2+c2) (+b+c)3 = 03+63+c3+3(0+b) (b+c)(c+a) a3+b3+c3_3abc-(atbtc)(a?+b+c?-ab-bc 00 बीजगणित सूत्र (a+b)2/ a१ + २ab + b२ = (a-b)2 = a?_ 2ab+b2 @7+62 = (@+6)2-2ab a2_b2 = (a+b)(a-b) = (a+b)2 = (a-b)2+ 4ab] (0+b)2 _ 40b | (a ~ b)2 3 (a-b)2 + 2ab 02+ 62 . 9 2(02+b2) = (+b)?+ (-b)2' (a+b)2_ (a-b)2 40b 3 (02b)2 _ (%b)2 ab a3+3a2b+3ab2+63 (a+b)3 = (a+b)3 @3+63+ 3ab(a+b) = @3-3@%b+3@b2-63 (0-b)3 > @-b) = @ -30 = 3ab(a-b) a3+b3 = (a+b)(a?-ab+b2) : Q3 + b3 = (+b)3 _ 3ಯb(o+b) (a-b)(a?+ab+b2) @3-63 = a3_63 = (a-b)3 + 3ab(a-b) (+b+C)2 = (2+b2+c2) + 2(0b+bc+ca) > (a2+62+c2) = (a+b+c)?_2(ab+bc+ca) > 2(abtbctca) = (a+b+c)?_(a2+b2+c2) (+b+c)3 = 03+63+c3+3(0+b) (b+c)(c+a) a3+b3+c3_3abc-(atbtc)(a?+b+c?-ab-bc 00 - ShareChat")