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Siliveru Anil Kumar
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#Educational Updates
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![Educational Updates - Sequences & Series Part 2: arithmetic_progression (AP) Arithmefic Progression (AP) a sequence in which the An arithmetic progression is difference between consecutive terms is constant difference Basic Terms first term a common difference (d) difference d ->common number of terms n Term Formula : an =a + (n-I)d ~ an =a + (n-I)d Nth +3each sfep d=3 14 2 Find 5th term of AP: 2,5, 8, Il.. Example d5 = 2+(5-|)>3 =2 Here 2 + |2 d = 3 = |4 n = 5 (n-I)d] 2 [2a] 2 [2q + (n-I)d] _ Sn Sum Formula Sn + Find sum of firsf 4 1erms : 2, 5, 8, II Example 2 [2x2+ (4-I)x3] = 2 [4+9] = 2x I3 = 26 S4 n=4 2 +8 5 1 २ + Pairs Sum = |3 (5+8 (2+|| missing term Use nth term -> find Exam Trick ofal value Use sum formula wrong value of d Common mistakes check formula incorrect, substitution carefully missing (n-I) AP has constant difference between terms. EduSphere Acqdemy Page 2 Sequences & Series Part 2: arithmetic_progression (AP) Arithmefic Progression (AP) a sequence in which the An arithmetic progression is difference between consecutive terms is constant difference Basic Terms first term a common difference (d) difference d ->common number of terms n Term Formula : an =a + (n-I)d ~ an =a + (n-I)d Nth +3each sfep d=3 14 2 Find 5th term of AP: 2,5, 8, Il.. Example d5 = 2+(5-|)>3 =2 Here 2 + |2 d = 3 = |4 n = 5 (n-I)d] 2 [2a] 2 [2q + (n-I)d] _ Sn Sum Formula Sn + Find sum of firsf 4 1erms : 2, 5, 8, II Example 2 [2x2+ (4-I)x3] = 2 [4+9] = 2x I3 = 26 S4 n=4 2 +8 5 1 २ + Pairs Sum = |3 (5+8 (2+|| missing term Use nth term -> find Exam Trick ofal value Use sum formula wrong value of d Common mistakes check formula incorrect, substitution carefully missing (n-I) AP has constant difference between terms. EduSphere Acqdemy Page 2 - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_298842_271ea994_1774448296985_sc.jpg?tenant=sc&referrer=pwa-sharechat-service&f=985_sc.jpg "Educational Updates - Sequences & Series Part 2: arithmetic_progression (AP) Arithmefic Progression (AP) a sequence in which the An arithmetic progression is difference between consecutive terms is constant difference Basic Terms first term a common difference (d) difference d ->common number of terms n Term Formula : an =a + (n-I)d ~ an =a + (n-I)d Nth +3each sfep d=3 14 2 Find 5th term of AP: 2,5, 8, Il.. Example d5 = 2+(5-|)>3 =2 Here 2 + |2 d = 3 = |4 n = 5 (n-I)d] 2 [2a] 2 [2q + (n-I)d] _ Sn Sum Formula Sn + Find sum of firsf 4 1erms : 2, 5, 8, II Example 2 [2x2+ (4-I)x3] = 2 [4+9] = 2x I3 = 26 S4 n=4 2 +8 5 1 २ + Pairs Sum = |3 (5+8 (2+|| missing term Use nth term -> find Exam Trick ofal value Use sum formula wrong value of d Common mistakes check formula incorrect, substitution carefully missing (n-I) AP has constant difference between terms. EduSphere Acqdemy Page 2 Sequences & Series Part 2: arithmetic_progression (AP) Arithmefic Progression (AP) a sequence in which the An arithmetic progression is difference between consecutive terms is constant difference Basic Terms first term a common difference (d) difference d ->common number of terms n Term Formula : an =a + (n-I)d ~ an =a + (n-I)d Nth +3each sfep d=3 14 2 Find 5th term of AP: 2,5, 8, Il.. Example d5 = 2+(5-|)>3 =2 Here 2 + |2 d = 3 = |4 n = 5 (n-I)d] 2 [2a] 2 [2q + (n-I)d] _ Sn Sum Formula Sn + Find sum of firsf 4 1erms : 2, 5, 8, II Example 2 [2x2+ (4-I)x3] = 2 [4+9] = 2x I3 = 26 S4 n=4 2 +8 5 1 २ + Pairs Sum = |3 (5+8 (2+|| missing term Use nth term -> find Exam Trick ofal value Use sum formula wrong value of d Common mistakes check formula incorrect, substitution carefully missing (n-I) AP has constant difference between terms. EduSphere Acqdemy Page 2 - ShareChat")