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Siliveru Anil Kumar - Author on ShareChat: Funny, Romantic, Videos, Shayari, Quotes
Siliveru Anil Kumar
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#Educational Updates #📖ఎడ్యుకేషన్✍ #💼TSPSC/ APPSC ప్రత్యేకం #🎓జాబ్ ప్రిపరేషన్📚 #🏆పోటీ పరీక్షల స్పెషల్
Educational Updates - Class 9 Science Part 6: Law of Conservation of Momentum The Law of Conservation of Momentum states : The total momentum of an isolated remains_constant system if no external force acts on it. Momentum is conserved . Total Momentum before Total Momentum after Forwula : Final Momentum M1M1 + M2u2 = MV1 + M2v2 Where: Mass of Object 1 m1 Mass of Object 2 m2 Initial Velocity of Object 1 M1 Velocity of Object 2 Initial 2 Final Velocity of Object 1 V1 Velocity of Object 2 Final V2 Example Numerical : Two cqrts collide qnd stick toqetker 4 kg 3w/s 11 m1 2 kg 5ms 02 /12 Final Velocity 4k 2k =? Solution: 3w/s 5 Ms (m1+ mறv M1U + mzUz 4x3+2x5 = (4+2)xV 12+10 = 6v Important for Exam : 22 = 6v always | followed Conservation of momentum is 22 V= in collisions and explosions | 6 No external force V = 3.67 Mls Momentum is conserved The final velocity is 3.६७ mls. Class 9 Science Part 6: Law of Conservation of Momentum The Law of Conservation of Momentum states : The total momentum of an isolated remains_constant system if no external force acts on it. Momentum is conserved . Total Momentum before Total Momentum after Forwula : Final Momentum M1M1 + M2u2 = MV1 + M2v2 Where: Mass of Object 1 m1 Mass of Object 2 m2 Initial Velocity of Object 1 M1 Velocity of Object 2 Initial 2 Final Velocity of Object 1 V1 Velocity of Object 2 Final V2 Example Numerical : Two cqrts collide qnd stick toqetker 4 kg 3w/s 11 m1 2 kg 5ms 02 /12 Final Velocity 4k 2k =? Solution: 3w/s 5 Ms (m1+ mறv M1U + mzUz 4x3+2x5 = (4+2)xV 12+10 = 6v Important for Exam : 22 = 6v always | followed Conservation of momentum is 22 V= in collisions and explosions | 6 No external force V = 3.67 Mls Momentum is conserved The final velocity is 3.६७ mls. - ShareChat