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Siliveru Anil Kumar
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#Educational Updates
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![Educational Updates - 0; 0 7 CUOU LO&GOIJ 0 1ರು 16 The LCM of three numbers is 7920 and their GCD is 12 Two of the numbers are 48 and 264. Using factor notation find the Find the smallest number which leaves a third number if one of its factors is 9. remeinder of 4 when dlvided by elther 8 or F 12 0r 14. 7920 = 24 X 32 X 5 * 11 SOLUTION LCM 22 > 3 GCD १२ 14 12 X 2 24 > 3 1st no. = 48 2 st no = 22 3 23 > 3 x 11 nd no. = 264 7 32 X 22 > 5 180 3rd no 23 > 3 X 7 = LCM 168 Smallest number = 168 + 4 = 172 768 17 Find the smallest number which leaves a The L.C M of two numbers is 180 and their remeinder of 4 when divided by either ৪ or 12 or 14. GCD is १२ Ifthe no numbers are ३६ and Y find the value of y. SOLUTION SOLUTION 12 12 2 14 180 = 22 X 32 * 5 LCM + 2 2 = 22 > 3 GCD 12 3 7 = 22 X 32 1st number = 36 23 * 3*7 = 168 0 LCM 22 > 3 X 5 60 Smallest number = 168 + 4 172 60 Prepared by Teacher Robert] 0; 0 7 CUOU LO&GOIJ 0 1ರು 16 The LCM of three numbers is 7920 and their GCD is 12 Two of the numbers are 48 and 264. Using factor notation find the Find the smallest number which leaves a third number if one of its factors is 9. remeinder of 4 when dlvided by elther 8 or F 12 0r 14. 7920 = 24 X 32 X 5 * 11 SOLUTION LCM 22 > 3 GCD १२ 14 12 X 2 24 > 3 1st no. = 48 2 st no = 22 3 23 > 3 x 11 nd no. = 264 7 32 X 22 > 5 180 3rd no 23 > 3 X 7 = LCM 168 Smallest number = 168 + 4 = 172 768 17 Find the smallest number which leaves a The L.C M of two numbers is 180 and their remeinder of 4 when divided by either ৪ or 12 or 14. GCD is १२ Ifthe no numbers are ३६ and Y find the value of y. SOLUTION SOLUTION 12 12 2 14 180 = 22 X 32 * 5 LCM + 2 2 = 22 > 3 GCD 12 3 7 = 22 X 32 1st number = 36 23 * 3*7 = 168 0 LCM 22 > 3 X 5 60 Smallest number = 168 + 4 172 60 Prepared by Teacher Robert] - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_56323_1d80818e_1774448453206_sc.jpg?tenant=sc&referrer=pwa-sharechat-service&f=206_sc.jpg "Educational Updates - 0; 0 7 CUOU LO&GOIJ 0 1ರು 16 The LCM of three numbers is 7920 and their GCD is 12 Two of the numbers are 48 and 264. Using factor notation find the Find the smallest number which leaves a third number if one of its factors is 9. remeinder of 4 when dlvided by elther 8 or F 12 0r 14. 7920 = 24 X 32 X 5 * 11 SOLUTION LCM 22 > 3 GCD १२ 14 12 X 2 24 > 3 1st no. = 48 2 st no = 22 3 23 > 3 x 11 nd no. = 264 7 32 X 22 > 5 180 3rd no 23 > 3 X 7 = LCM 168 Smallest number = 168 + 4 = 172 768 17 Find the smallest number which leaves a The L.C M of two numbers is 180 and their remeinder of 4 when divided by either ৪ or 12 or 14. GCD is १२ Ifthe no numbers are ३६ and Y find the value of y. SOLUTION SOLUTION 12 12 2 14 180 = 22 X 32 * 5 LCM + 2 2 = 22 > 3 GCD 12 3 7 = 22 X 32 1st number = 36 23 * 3*7 = 168 0 LCM 22 > 3 X 5 60 Smallest number = 168 + 4 172 60 Prepared by Teacher Robert] 0; 0 7 CUOU LO&GOIJ 0 1ರು 16 The LCM of three numbers is 7920 and their GCD is 12 Two of the numbers are 48 and 264. Using factor notation find the Find the smallest number which leaves a third number if one of its factors is 9. remeinder of 4 when dlvided by elther 8 or F 12 0r 14. 7920 = 24 X 32 X 5 * 11 SOLUTION LCM 22 > 3 GCD १२ 14 12 X 2 24 > 3 1st no. = 48 2 st no = 22 3 23 > 3 x 11 nd no. = 264 7 32 X 22 > 5 180 3rd no 23 > 3 X 7 = LCM 168 Smallest number = 168 + 4 = 172 768 17 Find the smallest number which leaves a The L.C M of two numbers is 180 and their remeinder of 4 when divided by either ৪ or 12 or 14. GCD is १२ Ifthe no numbers are ३६ and Y find the value of y. SOLUTION SOLUTION 12 12 2 14 180 = 22 X 32 * 5 LCM + 2 2 = 22 > 3 GCD 12 3 7 = 22 X 32 1st number = 36 23 * 3*7 = 168 0 LCM 22 > 3 X 5 60 Smallest number = 168 + 4 172 60 Prepared by Teacher Robert] - ShareChat")