Ajeet Yadav
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संख्याओं के नियम #Maths guru #🧮 सरल गणित / Reasoning #math formulas important varsha se #ajeet sir #class 10 # CBSE board
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"Scientific Approach"Maths#maths #math tricks![G ٤ ٥ ٨ ٤ ٢ R 1 Jajaran cenjang Lingkacn Juring Tenbereng 2 (a+k) Apoeema K L= 4 . t Sudu+ yor berceccn berniiai /8oe L0 = 2/o Tropesium LA-Le স meno ೨' Karena LC Semberons 1.$1!0 ٢ ٢٥٥ ٥ ٥+٥ « ٤ lingkofon hodap diowerer K = 4+b +C +d 2 Beah ketupat] LF+Ld 4C+LE = | 00 k = TL x c L= T* T2 TL x 21 L.jucin9 x L ^03 2 ` d, ` d2 K = 4 x $ 3609 Layang -layang 0 Qanjang K busur %0 Panjarg Loc juring AOG k = 2 (AD+A৫) busur AD c luos lingkoon 2 % 02 Ka . lingkaran L= daiam Segitiga Lingkoron 21 ١ ٢ = [= Segitig 2 Kl Sudul' Jumtah !$($-)($-b)($ -c) f= Ietic SUdU+NYA $ Lingkaran luar Segitiga 180 0 bl a+btc K = a b c h- -|< $= Zx ^xt 2 4L L = I C Rumus Horon A *८ s (s-0)(S-b)ls-c) L٥ 4 ,$($-@)($-b)($-() G ٤ ٥ ٨ ٤ ٢ R 1 Jajaran cenjang Lingkacn Juring Tenbereng 2 (a+k) Apoeema K L= 4 . t Sudu+ yor berceccn berniiai /8oe L0 = 2/o Tropesium LA-Le স meno ೨' Karena LC Semberons 1.$1!0 ٢ ٢٥٥ ٥ ٥+٥ « ٤ lingkofon hodap diowerer K = 4+b +C +d 2 Beah ketupat] LF+Ld 4C+LE = | 00 k = TL x c L= T* T2 TL x 21 L.jucin9 x L ^03 2 ` d, ` d2 K = 4 x $ 3609 Layang -layang 0 Qanjang K busur %0 Panjarg Loc juring AOG k = 2 (AD+A৫) busur AD c luos lingkoon 2 % 02 Ka . lingkaran L= daiam Segitiga Lingkoron 21 ١ ٢ = [= Segitig 2 Kl Sudul' Jumtah !$($-)($-b)($ -c) f= Ietic SUdU+NYA $ Lingkaran luar Segitiga 180 0 bl a+btc K = a b c h- -|< $= Zx ^xt 2 4L L = I C Rumus Horon A *८ s (s-0)(S-b)ls-c) L٥ 4 ,$($-@)($-b)($-()](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_817155_3807a17a_1784374812280_sc.jpg?tenant=sc&referrer=feed-service&f=280_sc.jpg)
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![20 Algebra_ Formulas Funaamental, Compound & Double -Angle Rules cosec 0 sec 0 sin 0 sin 0 tan 0 cot 0 Cos 0 cos 0 sin 0 sin20 Cos20 = 1 1+ cot20 cosec29 1 + tan?0 sec20 ton 0 C0$ cos 0 90%- 0 cos 0 sin 0 sin 6 Cos 0 cosec 0 sin (90% cot 0 sec0 0) = cos 0 sin 0 cos 0 sin 0 A+ 8 A+ B 90'_ 0 90"-0 sin(A+B) sinAcosB cos(A+ B) = cosAcosB] tan Cos(909 (909 0) = sin 0 0) cot 0 cosAsinB sinAsinB 13 A+ B A-B १५ 16 A-B A-B tanA + tanB sin (A -B) = sinAcosB Cos(A -B) tanB cosAcosB tanA tan(A+B) tan(A-B) cosAsinB sinAsinB 1-tanAtanB 1+tanAtanB 18 2sinAcosB ZcosAcosB sin(A+B) sin(A -B) Cos(A + B) + cos(A B) cos?A sin?A sin2A 2sinAcosA cos2A Tips: Memorize fundamental identities Tirst. the Use complementary (90*- 0), compound, and double-angle formulas to simplify problems 20 Algebra_ Formulas Funaamental, Compound & Double -Angle Rules cosec 0 sec 0 sin 0 sin 0 tan 0 cot 0 Cos 0 cos 0 sin 0 sin20 Cos20 = 1 1+ cot20 cosec29 1 + tan?0 sec20 ton 0 C0$ cos 0 90%- 0 cos 0 sin 0 sin 6 Cos 0 cosec 0 sin (90% cot 0 sec0 0) = cos 0 sin 0 cos 0 sin 0 A+ 8 A+ B 90'_ 0 90"-0 sin(A+B) sinAcosB cos(A+ B) = cosAcosB] tan Cos(909 (909 0) = sin 0 0) cot 0 cosAsinB sinAsinB 13 A+ B A-B १५ 16 A-B A-B tanA + tanB sin (A -B) = sinAcosB Cos(A -B) tanB cosAcosB tanA tan(A+B) tan(A-B) cosAsinB sinAsinB 1-tanAtanB 1+tanAtanB 18 2sinAcosB ZcosAcosB sin(A+B) sin(A -B) Cos(A + B) + cos(A B) cos?A sin?A sin2A 2sinAcosA cos2A Tips: Memorize fundamental identities Tirst. the Use complementary (90*- 0), compound, and double-angle formulas to simplify problems](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_870985_fbbebae_1783384869142_sc.jpg?tenant=sc&referrer=feed-service&f=142_sc.jpg)
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![G ٤ ٥ ٨ ٤ ٢ R 1 Tpie Pythagoras] Kesebangumn Pada secji +ioa b (7,24,2$) (3,4,$) ($,|2,|3) CxCc+c) (9,40,4) ( 8,Ir,I?) dan Keupatandu ೭x ( c+e ) 0 c2=0+b d2 Cxc S.Siku -Siku , jika C'>0'+৮' tumpu , ljiko c < 02+b loncip jika Jarar Cntar 2 titik IAb|= (7-7)+(42-9)" Perbandingon Sisi segitiga cilu - gilu rhufuf 0:1 C = |: |: 12 ৭ :৬ : C = ! : [3 :2 Sincysung] Gacis AB = AC LA= (Qo"-ZBuc A0 ७७ Ao? Gurs singcung Peerutuc^ coon AB' - (6,+6)4 0? Aptikosi garis singsung )1 Z1 G ٤ ٥ ٨ ٤ ٢ R 1 Tpie Pythagoras] Kesebangumn Pada secji +ioa b (7,24,2$) (3,4,$) ($,|2,|3) CxCc+c) (9,40,4) ( 8,Ir,I?) dan Keupatandu ೭x ( c+e ) 0 c2=0+b d2 Cxc S.Siku -Siku , jika C'>0'+৮' tumpu , ljiko c < 02+b loncip jika Jarar Cntar 2 titik IAb|= (7-7)+(42-9)" Perbandingon Sisi segitiga cilu - gilu rhufuf 0:1 C = |: |: 12 ৭ :৬ : C = ! : [3 :2 Sincysung] Gacis AB = AC LA= (Qo"-ZBuc A0 ७७ Ao? Gurs singcung Peerutuc^ coon AB' - (6,+6)4 0? Aptikosi garis singsung )1 Z1](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_257270_279b8c09_1782573255896_sc.jpg?tenant=sc&referrer=feed-service&f=896_sc.jpg)
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