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"Scientific Approach" - Author on ShareChat: Funny, Romantic, Videos, Shayari, Quotes
"Scientific Approach"
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Maths#math #maths #math tricks
maths - SPECIAL TRIANGLES & APPLICATIONS GEOMETRY Equilateral Triangle All sides equal All angles 609 All centres |, 0, G,H coincide at same point AD is median altitude angle bisector perpendicular bisector a 13 a2 Height: h= Area: Area = 609 2 609 3 Circumradius: R = ೩ 3h ೩ Inradius: [ 13 213 Area (circumcircle) Area (incircle) = 4 : 1 R:r=2:1 Equilateral Triangle Relations Side Height Area height = V3k - area = V3 k2 If side 2K - [3a a2 Isosceles Right Triangle Isosceles Triangle Angles: 459, 459, 909 Two sides equal (AB AC) If hypotenuse = H All four centres lie on AD H Legs 1a? _ L Height: AD H 459 459 Area = 4V4a2 - b2 Area C Perimeter = H(V2 + 1) Right Angle Triangle r= P+8-H Relations: r+R=P+8 One angle 909 4 Inscribed in a semicircle R= 80 = shortest median = BG = H GO = H 3' Area: Area =r x $ = S(S - 2R) = r- + ZrR Odd number method >(3,4,5), (5,12,13) Pythagorean Triplets Even number method _ (6,8,10) (8,15,17) Square Inscribed in a Triangle Area Results If base segments = X and y Ifx2+y2 =22 Xy Side of square Area of shaded part = a = X +y 72 Area of AABC ab In right triangle: Side a +b abc Side (largest square): y = where x >y 32 + b2 + ab Scalene Triangle Areaः Area =vs(s All sides unequal a)(s -b)(s -c) Perimeter: P = ೩+ b + C Area = r x $ btc Semi perimeter: $ = 2+ abc Area 4R SPECIAL TRIANGLES & APPLICATIONS GEOMETRY Equilateral Triangle All sides equal All angles 609 All centres |, 0, G,H coincide at same point AD is median altitude angle bisector perpendicular bisector a 13 a2 Height: h= Area: Area = 609 2 609 3 Circumradius: R = ೩ 3h ೩ Inradius: [ 13 213 Area (circumcircle) Area (incircle) = 4 : 1 R:r=2:1 Equilateral Triangle Relations Side Height Area height = V3k - area = V3 k2 If side 2K - [3a a2 Isosceles Right Triangle Isosceles Triangle Angles: 459, 459, 909 Two sides equal (AB AC) If hypotenuse = H All four centres lie on AD H Legs 1a? _ L Height: AD H 459 459 Area = 4V4a2 - b2 Area C Perimeter = H(V2 + 1) Right Angle Triangle r= P+8-H Relations: r+R=P+8 One angle 909 4 Inscribed in a semicircle R= 80 = shortest median = BG = H GO = H 3' Area: Area =r x $ = S(S - 2R) = r- + ZrR Odd number method >(3,4,5), (5,12,13) Pythagorean Triplets Even number method _ (6,8,10) (8,15,17) Square Inscribed in a Triangle Area Results If base segments = X and y Ifx2+y2 =22 Xy Side of square Area of shaded part = a = X +y 72 Area of AABC ab In right triangle: Side a +b abc Side (largest square): y = where x >y 32 + b2 + ab Scalene Triangle Areaः Area =vs(s All sides unequal a)(s -b)(s -c) Perimeter: P = ೩+ b + C Area = r x $ btc Semi perimeter: $ = 2+ abc Area 4R - ShareChat