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MATH Solutions By PHANI
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![📖ఎడ్యుకేషన్✍ - 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_276286_30cb8c1a_1774501270214_sc.jpg?tenant=sc&referrer=pwa-sharechat-service&f=214_sc.jpg "📖ఎడ్యుకేషన్✍ - 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C\" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C\" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer - ShareChat")