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![exams - Chemistry Formula Series Page 1 Mole_Concept] Important Formulas Number of Moles 1) number of moles ٨ > m > mass of substance m n = M M _ molqr mass 2) Avogadro Relation particles N>> number of number of moles ٨ » nxNal N= Avogadro number Na > 3) Avogadro Constant number of particles Na 23 =1 Na 6.022 *10 mol one mole in < Molar Mass Relation 4) M > molor mass M=m m - mqss number of moles n > Gas Volume at STP 5) V ~ volume of gas (liters) V = 22.4 n n > number of moles 6)| Density Relation] density p -> m p = m mass volume > Chemistry Formula Series Page 1 Mole_Concept] Important Formulas Number of Moles 1) number of moles ٨ > m > mass of substance m n = M M _ molqr mass 2) Avogadro Relation particles N>> number of number of moles ٨ » nxNal N= Avogadro number Na > 3) Avogadro Constant number of particles Na 23 =1 Na 6.022 *10 mol one mole in < Molar Mass Relation 4) M > molor mass M=m m - mqss number of moles n > Gas Volume at STP 5) V ~ volume of gas (liters) V = 22.4 n n > number of moles 6)| Density Relation] density p -> m p = m mass volume > - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_38207_1f6cfbaf_1774823036034_sc.jpg?tenant=sc&referrer=pwa-sharechat-service&f=034_sc.jpg "exams - Chemistry Formula Series Page 1 Mole_Concept] Important Formulas Number of Moles 1) number of moles ٨ > m > mass of substance m n = M M _ molqr mass 2) Avogadro Relation particles N>> number of number of moles ٨ » nxNal N= Avogadro number Na > 3) Avogadro Constant number of particles Na 23 =1 Na 6.022 *10 mol one mole in < Molar Mass Relation 4) M > molor mass M=m m - mqss number of moles n > Gas Volume at STP 5) V ~ volume of gas (liters) V = 22.4 n n > number of moles 6)| Density Relation] density p -> m p = m mass volume > Chemistry Formula Series Page 1 Mole_Concept] Important Formulas Number of Moles 1) number of moles ٨ > m > mass of substance m n = M M _ molqr mass 2) Avogadro Relation particles N>> number of number of moles ٨ » nxNal N= Avogadro number Na > 3) Avogadro Constant number of particles Na 23 =1 Na 6.022 *10 mol one mole in < Molar Mass Relation 4) M > molor mass M=m m - mqss number of moles n > Gas Volume at STP 5) V ~ volume of gas (liters) V = 22.4 n n > number of moles 6)| Density Relation] density p -> m p = m mass volume > - ShareChat")