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MATH Solutions By PHANI
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#📘ఇంటర్ సైన్స్ & మ్యాథ్స్
#➗10th గణితం
#👩💻టెట్/DSC ప్రత్యేకం
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![📘ఇంటర్ సైన్స్ & మ్యాథ్స్ - Coordinate Geometry Formulas & Concepts Distance Formula:| (X1,91) and (X2,92) Distance between two Points (X2-X1)?(92-U1)2 d= 20 Section Formula: 1. Internal Division (m:mz): P(x,y) Coordinates of the point P(x,y1), dividing m-mz (X೭' the line joining (X५१) & 92), internallu, in m= m2 A- the ratio m:mz given by: are B X m-m2 I2X1 X= m11X2+ m192 + m291 ৬ = m1 +m2 mi + mz Section Formula: line P is the midpoint of thel joining (X191) & (X2.92): X1+X2 P (X1+X2) ५१ + ५२ (91+Y2) P= 'ೆ 2 2 2 2 Area रof a Triangle (X292" having vertices (X1,91) & Area of a triangle 2 [Xi (92-93)+*2(93-91)+*3 (91-92)] 4= B 50 Collinearity of Points] tu To prove three points (X1, 91), (X2 92), (X2,93) are collinear; prove mt Area रof A A ೆಕ 247 Pythagoras Theorem: right-angled triangle, the square of the hypotenuse In a to the ratio of the squares of their is equal corresponding sides:| B b Coordinate Geometry Formulas & Concepts Distance Formula:| (X1,91) and (X2,92) Distance between two Points (X2-X1)?(92-U1)2 d= 20 Section Formula: 1. Internal Division (m:mz): P(x,y) Coordinates of the point P(x,y1), dividing m-mz (X೭' the line joining (X५१) & 92), internallu, in m= m2 A- the ratio m:mz given by: are B X m-m2 I2X1 X= m11X2+ m192 + m291 ৬ = m1 +m2 mi + mz Section Formula: line P is the midpoint of thel joining (X191) & (X2.92): X1+X2 P (X1+X2) ५१ + ५२ (91+Y2) P= 'ೆ 2 2 2 2 Area रof a Triangle (X292" having vertices (X1,91) & Area of a triangle 2 [Xi (92-93)+*2(93-91)+*3 (91-92)] 4= B 50 Collinearity of Points] tu To prove three points (X1, 91), (X2 92), (X2,93) are collinear; prove mt Area रof A A ೆಕ 247 Pythagoras Theorem: right-angled triangle, the square of the hypotenuse In a to the ratio of the squares of their is equal corresponding sides:| B b - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_633006_c1b94cc_1767711631502_sc.jpg?tenant=sc&referrer=pwa-sharechat-service&f=502_sc.jpg "📘ఇంటర్ సైన్స్ & మ్యాథ్స్ - Coordinate Geometry Formulas & Concepts Distance Formula:| (X1,91) and (X2,92) Distance between two Points (X2-X1)?(92-U1)2 d= 20 Section Formula: 1. Internal Division (m:mz): P(x,y) Coordinates of the point P(x,y1), dividing m-mz (X೭' the line joining (X५१) & 92), internallu, in m= m2 A- the ratio m:mz given by: are B X m-m2 I2X1 X= m11X2+ m192 + m291 ৬ = m1 +m2 mi + mz Section Formula: line P is the midpoint of thel joining (X191) & (X2.92): X1+X2 P (X1+X2) ५१ + ५२ (91+Y2) P= 'ೆ 2 2 2 2 Area रof a Triangle (X292\" having vertices (X1,91) & Area of a triangle 2 [Xi (92-93)+*2(93-91)+*3 (91-92)] 4= B 50 Collinearity of Points] tu To prove three points (X1, 91), (X2 92), (X2,93) are collinear; prove mt Area रof A A ೆಕ 247 Pythagoras Theorem: right-angled triangle, the square of the hypotenuse In a to the ratio of the squares of their is equal corresponding sides:| B b Coordinate Geometry Formulas & Concepts Distance Formula:| (X1,91) and (X2,92) Distance between two Points (X2-X1)?(92-U1)2 d= 20 Section Formula: 1. Internal Division (m:mz): P(x,y) Coordinates of the point P(x,y1), dividing m-mz (X೭' the line joining (X५१) & 92), internallu, in m= m2 A- the ratio m:mz given by: are B X m-m2 I2X1 X= m11X2+ m192 + m291 ৬ = m1 +m2 mi + mz Section Formula: line P is the midpoint of thel joining (X191) & (X2.92): X1+X2 P (X1+X2) ५१ + ५२ (91+Y2) P= 'ೆ 2 2 2 2 Area रof a Triangle (X292\" having vertices (X1,91) & Area of a triangle 2 [Xi (92-93)+*2(93-91)+*3 (91-92)] 4= B 50 Collinearity of Points] tu To prove three points (X1, 91), (X2 92), (X2,93) are collinear; prove mt Area रof A A ೆಕ 247 Pythagoras Theorem: right-angled triangle, the square of the hypotenuse In a to the ratio of the squares of their is equal corresponding sides:| B b - ShareChat")