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![jee - JEE MAIN २०२६ Let the maximum value of (sin 'x)' + (cos 'x)' for 23 13 ` m 2 be where (1, 1) = ] . gcd TT Xe V2 2 n {=} Then m +n is to equal 21 Jan - Shift 2 JEE MAIN २०२६ Let the maximum value of (sin 'x)' + (cos 'x)' for 23 13 ` m 2 be where (1, 1) = ] . gcd TT Xe V2 2 n {=} Then m +n is to equal 21 Jan - Shift 2 - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_155842_3070698d_1775031154417_sc.jpg?tenant=sc&referrer=user-profile-service%2FrequestType50&f=417_sc.jpg "jee - JEE MAIN २०२६ Let the maximum value of (sin 'x)' + (cos 'x)' for 23 13 ` m 2 be where (1, 1) = ] . gcd TT Xe V2 2 n {=} Then m +n is to equal 21 Jan - Shift 2 JEE MAIN २०२६ Let the maximum value of (sin 'x)' + (cos 'x)' for 23 13 ` m 2 be where (1, 1) = ] . gcd TT Xe V2 2 n {=} Then m +n is to equal 21 Jan - Shift 2 - ShareChat")
![👩💻టెట్/DSC ప్రత్యేకం - CONIC SECTIONS JEE Mains EAPCET -OET BITSHI UIT (Preparation Problems] Video -01 PHIISNDRA WAIHS WAIHS CONIC SECTIONS JEE Mains EAPCET -OET BITSHI UIT (Preparation Problems] Video -01 PHIISNDRA WAIHS WAIHS - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_531085_32fc1f21_1774929529877_sc.jpg?tenant=sc&referrer=user-profile-service%2FrequestType50&f=877_sc.jpg "👩💻టెట్/DSC ప్రత్యేకం - CONIC SECTIONS JEE Mains EAPCET -OET BITSHI UIT (Preparation Problems] Video -01 PHIISNDRA WAIHS WAIHS CONIC SECTIONS JEE Mains EAPCET -OET BITSHI UIT (Preparation Problems] Video -01 PHIISNDRA WAIHS WAIHS - ShareChat")
![📖ఎడ్యుకేషన్✍ - 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer - ShareChat](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_276286_30cb8c1a_1774501270214_sc.jpg?tenant=sc&referrer=user-profile-service%2FrequestType50&f=214_sc.jpg "📖ఎడ్యుకేషన్✍ - 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C\" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer 0 Evaluate [sin' (2x+1)dx sin2(2x+I) sin (2x +/)dx Solution: f ( C0$?(2x+/)) sin(2x +I) dx - Letl cos (2x+1) u = du Sin(2x+I) . 2dX = ೦ sin(2x +I) dx 2du = ' J (|-02) . (-2) du MATH Solutions By PHANI -2 ] (I-u2) du = -2 [u - ತ3] +C (2x+I) + C\" COs3 Cos(2x+|)- 2 3 چcos3(2x+|)+C _ cos(2x+|) + Final Answer - ShareChat")
