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MATH Solutions By PHANI
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#➗10th గణితం
➗10th గణితం - Cculote He 48C of te b iavgle area Isosceles Area ०f 2*bxh tiang le o 6=0*+07 fytuagoreav C qcorem: 8C c*=a`+b 0 0= 6*+4 12' c 100 36 + 4 C = Area= 1 * 6 * k Voa = 12 > 8 -* K= & C [+8_c Cculote He 48C of te b iavgle area Isosceles Area ०f 2*bxh tiang le o 6=0*+07 fytuagoreav C qcorem: 8C c*=a`+b 0 0= 6*+4 12' c 100 36 + 4 C = Area= 1 * 6 * k Voa = 12 > 8 -* K= & C [+8_c - ShareChat
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#☸🙏సూర్యనారాయణ స్వామి
☸🙏సూర్యనారాయణ స్వామి - ShareChat
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#🏆పోటీ పరీక్షల స్పెషల్ #➗10th గణితం #👩‍💻టెట్/DSC ప్రత్యేకం #📘ఇంటర్ సైన్స్ & మ్యాథ్స్
📘ఇంటర్ సైన్స్ & మ్యాథ్స్ - ShareChat
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MATH Solutions By PHANI
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#🌅శుభోదయం #♥ప్రేమతో శుభోదయం🌄 #ఓ మంచిమాట
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MATH Solutions By PHANI - Author on ShareChat: Funny, Romantic, Videos, Shayari, Quotes
MATH Solutions By PHANI
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#🌅శుభోదయం #♥ప్రేమతో శుభోదయం🌄 #🤝Have a Good Day🤩 #🌷గురువారం స్పెషల్ విషెస్
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MATH Solutions By PHANI
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#📘ఇంటర్ సైన్స్ & మ్యాథ్స్ #🏆పోటీ పరీక్షల స్పెషల్ #👩‍💻టెట్/DSC ప్రత్యేకం #➗10th గణితం
📘ఇంటర్ సైన్స్ & మ్యాథ్స్ - ShareChat
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MATH Solutions By PHANI
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#🏆పోటీ పరీక్షల స్పెషల్ #📘ఇంటర్ సైన్స్ & మ్యాథ్స్ #👩‍💻టెట్/DSC ప్రత్యేకం #intermediate
🏆పోటీ పరీక్షల స్పెషల్ - Statistics 15 MODE ONUO2Ep DArA n-observations Ms observations (xi) "occuring" maximum The number of tires Denoted by = ४ Also callert as "Average/A M" Arithraetic Mean case , two nurabers occuring sarne nurber data then given 01 tirnes set said S//1 o nll pUsriYntions' "Bi-Modal" | Total obsarvacions Ne Weighted Meon: Relation between Mean, Median & Mode:| "1-obseivations wcights Corresponding for moderately Made = 3Median 2Mean 49 ಹ ctricnl d೧ta Xv' CWcightcd Mican ) ror symmctrical Mode = Median Mean 0s notion dntq Woe Combined Meqn: Quesuon IF mean of ni observation is %; and for nz Q. The weighted mzar of the first n natural observation is Xz whose weigats the Aurnoer 00 eqvql ' Are squares of the corresponding number is n X -nXi Then cowbined Wean Sn(n 1) () (B) 2121 -1 MEDIAN n(n = 1) (C) ( + 1)(2^ -1) (D) -+ *2+ *3* Sol. 12,3 + = ^_ Ooserv n-observations (terms) First increasing arrange 17 n? _ Wrighe given data 2,3 +2 decreasing order now 1* + 2 417 Wl Median (^;=)" +--2- Value of term when n € odd 4+1) | A(A-1) A(, value of observation ^(2! + 1)(^ +1) observation when n ః even 3n(+ 1)fnf: 2(2n + 1) Statistics 15 MODE ONUO2Ep DArA n-observations Ms observations (xi) "occuring" maximum The number of tires Denoted by = ४ Also callert as "Average/A M" Arithraetic Mean case , two nurabers occuring sarne nurber data then given 01 tirnes set said S//1 o nll pUsriYntions' "Bi-Modal" | Total obsarvacions Ne Weighted Meon: Relation between Mean, Median & Mode:| "1-obseivations wcights Corresponding for moderately Made = 3Median 2Mean 49 ಹ ctricnl d೧ta Xv' CWcightcd Mican ) ror symmctrical Mode = Median Mean 0s notion dntq Woe Combined Meqn: Quesuon IF mean of ni observation is %; and for nz Q. The weighted mzar of the first n natural observation is Xz whose weigats the Aurnoer 00 eqvql ' Are squares of the corresponding number is n X -nXi Then cowbined Wean Sn(n 1) () (B) 2121 -1 MEDIAN n(n = 1) (C) ( + 1)(2^ -1) (D) -+ *2+ *3* Sol. 12,3 + = ^_ Ooserv n-observations (terms) First increasing arrange 17 n? _ Wrighe given data 2,3 +2 decreasing order now 1* + 2 417 Wl Median (^;=)" +--2- Value of term when n € odd 4+1) | A(A-1) A(, value of observation ^(2! + 1)(^ +1) observation when n ః even 3n(+ 1)fnf: 2(2n + 1) - ShareChat
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#🏆పోటీ పరీక్షల స్పెషల్ #📘ఇంటర్ సైన్స్ & మ్యాథ్స్ #👩‍💻టెట్/DSC ప్రత్యేకం #Intermediate Maths Problem Solving
🏆పోటీ పరీక్షల స్పెషల్ - EAPCET (APITG (CSX-Sx)(2+2Simدx) NDA BITSAT KET JEE Mag] Cx +Sim) Si2x +C ((G31-Sim)2 (1+Simn2x)dz C22 + C 2) Cx+Simz) TO२ ७ + c 3) (Cogat-Suna) (($2+Sun 7 Ct 21 +C 2SmzGxd) 2 Cox+sim ) (Cx - Smx ) (0Sx(+Sunx) dz 2 ((81+Smnx) ( (CSit-Simz) (CoBx+Simx) dsc 2 २( (@९ 2 X-Simz) dx =2 ( (82x dx 2 ( Smzz) +c MATH Solutions By PHANI Sin2+C / B @MATH Solutions @Phaneendra Va PHAN EAPCET (APITG (CSX-Sx)(2+2Simدx) NDA BITSAT KET JEE Mag] Cx +Sim) Si2x +C ((G31-Sim)2 (1+Simn2x)dz C22 + C 2) Cx+Simz) TO२ ७ + c 3) (Cogat-Suna) (($2+Sun 7 Ct 21 +C 2SmzGxd) 2 Cox+sim ) (Cx - Smx ) (0Sx(+Sunx) dz 2 ((81+Smnx) ( (CSit-Simz) (CoBx+Simx) dsc 2 २( (@९ 2 X-Simz) dx =2 ( (82x dx 2 ( Smzz) +c MATH Solutions By PHANI Sin2+C / B @MATH Solutions @Phaneendra Va PHAN - ShareChat
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#🏆పోటీ పరీక్షల స్పెషల్ #➗10th గణితం #👩‍💻టెట్/DSC ప్రత్యేకం
🏆పోటీ పరీక్షల స్పెషల్ - Ch-6: Squqres_ qnd Squqre_Roots Part 4 Finding Squqre Root by Long Division Method 7. from right to left 1. Group digits in Method: pqirs 2. Find the Iorgest number whose Find the largest number whose square is < first pqirldigit. 3. Subtract and bring down next pair: 4. Double the quotient for the new divisor's first part: Solutions Example: Find the square root of 529. By PHANI 3 2 5 29 2 = 4 Therefore; 529 23 3 43 29 1 29 -1 Note: This method is useful for large numbers qnd decimdls. Ch-6: Squqres_ qnd Squqre_Roots Part 4 Finding Squqre Root by Long Division Method 7. from right to left 1. Group digits in Method: pqirs 2. Find the Iorgest number whose Find the largest number whose square is < first pqirldigit. 3. Subtract and bring down next pair: 4. Double the quotient for the new divisor's first part: Solutions Example: Find the square root of 529. By PHANI 3 2 5 29 2 = 4 Therefore; 529 23 3 43 29 1 29 -1 Note: This method is useful for large numbers qnd decimdls. - ShareChat