Ajeet Yadav
1K views • 5 months ago
# Class 10th Topic:Trigonometry formula #Maths guru #🧮 सरल गणित / Reasoning #math formulas important varsha se #👩🌾खान सर मोटिवेशन💡
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❤️❤️AVIKA ❤️❤️#रिजनिंग अथवा सरल गणित हल करने से मानसिक स्वास्थ्य सही रहता है #Maths guru #maths formula #maths
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![G ٤ ٥ ٨ ٤ ٢ R 1 Jajaran cenjang Lingkacn Juring Tenbereng 2 (a+k) Apoeema K L= 4 . t Sudu+ yor berceccn berniiai /8oe L0 = 2/o Tropesium LA-Le স meno ೨' Karena LC Semberons 1.$1!0 ٢ ٢٥٥ ٥ ٥+٥ « ٤ lingkofon hodap diowerer K = 4+b +C +d 2 Beah ketupat] LF+Ld 4C+LE = | 00 k = TL x c L= T* T2 TL x 21 L.jucin9 x L ^03 2 ` d, ` d2 K = 4 x $ 3609 Layang -layang 0 Qanjang K busur %0 Panjarg Loc juring AOG k = 2 (AD+A৫) busur AD c luos lingkoon 2 % 02 Ka . lingkaran L= daiam Segitiga Lingkoron 21 ١ ٢ = [= Segitig 2 Kl Sudul' Jumtah !$($-)($-b)($ -c) f= Ietic SUdU+NYA $ Lingkaran luar Segitiga 180 0 bl a+btc K = a b c h- -|< $= Zx ^xt 2 4L L = I C Rumus Horon A *८ s (s-0)(S-b)ls-c) L٥ 4 ,$($-@)($-b)($-() G ٤ ٥ ٨ ٤ ٢ R 1 Jajaran cenjang Lingkacn Juring Tenbereng 2 (a+k) Apoeema K L= 4 . t Sudu+ yor berceccn berniiai /8oe L0 = 2/o Tropesium LA-Le স meno ೨' Karena LC Semberons 1.$1!0 ٢ ٢٥٥ ٥ ٥+٥ « ٤ lingkofon hodap diowerer K = 4+b +C +d 2 Beah ketupat] LF+Ld 4C+LE = | 00 k = TL x c L= T* T2 TL x 21 L.jucin9 x L ^03 2 ` d, ` d2 K = 4 x $ 3609 Layang -layang 0 Qanjang K busur %0 Panjarg Loc juring AOG k = 2 (AD+A৫) busur AD c luos lingkoon 2 % 02 Ka . lingkaran L= daiam Segitiga Lingkoron 21 ١ ٢ = [= Segitig 2 Kl Sudul' Jumtah !$($-)($-b)($ -c) f= Ietic SUdU+NYA $ Lingkaran luar Segitiga 180 0 bl a+btc K = a b c h- -|< $= Zx ^xt 2 4L L = I C Rumus Horon A *८ s (s-0)(S-b)ls-c) L٥ 4 ,$($-@)($-b)($-()](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_817155_3807a17a_1784374812280_sc.jpg?tenant=sc&referrer=feed-service&f=280_sc.jpg)
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SJ Classes#youtube ▶️ Sagar Jha Classes #maths #squareroot #percentage #sjclasses![२५% का वर्गमूल क्या होगा? Find 25% SQUARE ROOT 25% ][ OF Sagar Jha classes २५% का वर्गमूल क्या होगा? Find 25% SQUARE ROOT 25% ][ OF Sagar Jha classes](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_432732_1618599d_1784373431551_sc.jpg?tenant=sc&referrer=feed-service&f=551_sc.jpg)
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@shersingh#maths formula #Maths guru #maths 🥰🥰🥰🥰😍😍😍😍😘😘😘😘😘
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![20 Algebra_ Formulas Funaamental, Compound & Double -Angle Rules cosec 0 sec 0 sin 0 sin 0 tan 0 cot 0 Cos 0 cos 0 sin 0 sin20 Cos20 = 1 1+ cot20 cosec29 1 + tan?0 sec20 ton 0 C0$ cos 0 90%- 0 cos 0 sin 0 sin 6 Cos 0 cosec 0 sin (90% cot 0 sec0 0) = cos 0 sin 0 cos 0 sin 0 A+ 8 A+ B 90'_ 0 90"-0 sin(A+B) sinAcosB cos(A+ B) = cosAcosB] tan Cos(909 (909 0) = sin 0 0) cot 0 cosAsinB sinAsinB 13 A+ B A-B १५ 16 A-B A-B tanA + tanB sin (A -B) = sinAcosB Cos(A -B) tanB cosAcosB tanA tan(A+B) tan(A-B) cosAsinB sinAsinB 1-tanAtanB 1+tanAtanB 18 2sinAcosB ZcosAcosB sin(A+B) sin(A -B) Cos(A + B) + cos(A B) cos?A sin?A sin2A 2sinAcosA cos2A Tips: Memorize fundamental identities Tirst. the Use complementary (90*- 0), compound, and double-angle formulas to simplify problems 20 Algebra_ Formulas Funaamental, Compound & Double -Angle Rules cosec 0 sec 0 sin 0 sin 0 tan 0 cot 0 Cos 0 cos 0 sin 0 sin20 Cos20 = 1 1+ cot20 cosec29 1 + tan?0 sec20 ton 0 C0$ cos 0 90%- 0 cos 0 sin 0 sin 6 Cos 0 cosec 0 sin (90% cot 0 sec0 0) = cos 0 sin 0 cos 0 sin 0 A+ 8 A+ B 90'_ 0 90"-0 sin(A+B) sinAcosB cos(A+ B) = cosAcosB] tan Cos(909 (909 0) = sin 0 0) cot 0 cosAsinB sinAsinB 13 A+ B A-B १५ 16 A-B A-B tanA + tanB sin (A -B) = sinAcosB Cos(A -B) tanB cosAcosB tanA tan(A+B) tan(A-B) cosAsinB sinAsinB 1-tanAtanB 1+tanAtanB 18 2sinAcosB ZcosAcosB sin(A+B) sin(A -B) Cos(A + B) + cos(A B) cos?A sin?A sin2A 2sinAcosA cos2A Tips: Memorize fundamental identities Tirst. the Use complementary (90*- 0), compound, and double-angle formulas to simplify problems](https://cdn4.sharechat.com/bd5223f_s1w/compressed_gm_40_img_870985_fbbebae_1783384869142_sc.jpg?tenant=sc&referrer=feed-service&f=142_sc.jpg)
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